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> >The way vararg currently works, "#..."
> >wouldn't syntactically make sense, though I agree the way it currently
> >works is awkward and as I understand it's being changed in 5.2.
> 
> That's good news.

Unfortunately it is not true ;) The expression "#..." does make sense
and has a clear meaning, consistent with #f(x) (and with -f(x), -...,
etc.). And there are no plans to change varargs in 5.2.

-- Roberto