Re: runtime execution fails why?

function r(value, repeats)

return string.format("value = %d repeats = %3d", value, repeats)

end

f = loadstring("r(3,4)")

print ("f() = <“, f(), ”>")

Alas, this returns: f = < nil >

Clearly the call to r doesn’t has the result I had in mind.

What is my error here?

Hans van der Meer

On 18 jan. 2014, at 17:37, Victor Bombi <sonoro@telefonica.net> wrote:

"The environment of the returned function is the global environment."

http://www.lua.org/manual/5.1/manual.html#pdf-load
----- Original Message -----
From: H. van der Meer
To: Lua mailing list
Sent: Saturday, January 18, 2014 5:21 PM
Subject: runtime execution fails why?

Collecting function calls for example r(3,4) in a table I would like to execute these. But testing reveals I do something wrong.
The program in essence:

local function test(t)
local function r(a,b) return string.format(“a = %d b = %d”, a, b) end
for i =1,10 do
local f = load(t[i])
f()
end
end

This fails with error message:
/usr/local/bin/lua: [string "r(2,364)"]:1: attempt to call global 'r' (a nil value)
stack traceback:
[string "r(2,364)"]:1: in function 'f'

What is wrong in my code? Why is function r considered global and not found in the scope of function test(t)?

Thanks in advance
Hans van der Meer