Re: runtime execution fails why?

[Volodymyr Bezobiuk <dedoogun@...>]

Because load() creates own local scope with no upvalues from current local scope. You can fix this for your case with something like

for i =1,10 do  _ENV = setmetatable({ r = r }, { __index = _ENV })

On Sat, Jan 18, 2014 at 6:21 PM, H. van der Meer <H.vanderMeer@uva.nl> wrote:

Collecting function calls for example  r(3,4) in a table I would like to execute these. But testing reveals I do something wrong.

The program in essence:

local function test(t)

local function r(a,b) return string.format(“a = %d b = %d”, a, b) end

for i =1,10 do

local f = load(t[i])

f()

end

end

This fails with error message:

/usr/local/bin/lua: [string "r(2,364)"]:1: attempt to call global 'r' (a nil value)

stack traceback:

[string "r(2,364)"]:1: in function 'f'

What is wrong in my code? Why is function r considered global and not found in the scope of function test(t)?

Thanks in advance

Hans van der Meer