Re: runtime execution fails why?

[Volodymyr Bezobiuk <dedoogun@...>]

f = loadstring("return r(3,4)")  --- :)

On Sat, Jan 18, 2014 at 6:55 PM, H. van der Meer <H.vanderMeer@uva.nl> wrote:

Thanks, that helped me running the code and I saw I should have used loadstring instead of load.

But then the second hurdle arises:

function r(value, repeats)

    return string.format("value = %d repeats = %3d", value, repeats)

end

f = loadstring("r(3,4)")

print ("f() = <“, f(), ”>")

Alas, this returns: f = < nil  >

Clearly the call to r doesn’t has the result I had in mind.

What is my error here?

Hans van der Meer

On 18 jan. 2014, at 17:37, Victor Bombi <sonoro@telefonica.net> wrote:

"The environment of the returned function is the global environment."

 

http://www.lua.org/manual/5.1/manual.html#pdf-load

----- Original Message -----

From: H. van der Meer

To: Lua mailing list

Sent: Saturday, January 18, 2014 5:21 PM

Subject: runtime execution fails why?

Collecting function calls for example  r(3,4) in a table I would like to execute these. But testing reveals I do something wrong.

The program in essence:

local function test(t)

local function r(a,b) return string.format(“a = %d b = %d”, a, b) end

for i =1,10 do

local f = load(t[i])

f()

end

end

This fails with error message:

/usr/local/bin/lua: [string "r(2,364)"]:1: attempt to call global 'r' (a nil value)

stack traceback:

[string "r(2,364)"]:1: in function 'f'

What is wrong in my code? Why is function r considered global and not found in the scope of function test(t)?

Thanks in advance

Hans van der Meer