Re: Return an exit code without os.exit()?

[Geoff Leyland <geoff_leyland@...>]

On 8/10/2009, at 11:24 AM, Robert G. Jakabosky wrote:
> Put this in "luacov_on_exit.lua":
> --- start
> require('luacov')
> local luacovlock = os.tmpname()
> function on_exit()
>    os.remove(luacovlock)
>    stats.save_stats(data, statsfile)
>    stats.stop_stats(statsfile)
> end
> on_exit_trick = io.open(luacovlock, "w")
> debug.setmetatable(on_exit_trick, { __gc = on_exit } )
> local exit=os.exit
> os.exit = function(...)
>   on_exit()
>   exit(...)
> end
> --- end
>
> Then run your program with:
> lua -lluacov_on_exit script.lua

Yeah, that's right.  For some reason I was stuck thinking I didn't  
want to change lua, but I've already made lots of changes to luacov.   
Thanks for pointing that out.