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- Subject: Re: Return an exit code without os.exit()?
- From: "Robert G. Jakabosky" <bobby@...>
- Date: Wed, 7 Oct 2009 03:08:05 -0700
On Wednesday 07, Geoff Leyland wrote:
> On 7/10/2009, at 10:24 PM, Jerome Vuarand wrote:
> > 2009/10/7 Geoff Leyland <geoff_leyland@fastmail.fm>:
> >> Is there a way to return an exit code from a Lua script without
> >> calling
> >> os.exit()?
> >>
> >> I'm using luacov, and if you call os.exit(), it doesn't write any
> >> statistics. I'd also like my script to return 1 or 0. As far as I
> >> can
> >> tell, the return value from a top-level script does not seem to be
> >> used for
> >> an exit code, but hopefully someone can tell me I'm wrong.
> >
> > Looking at the code in lua.c, it seems the return value of the script
> > is ignored. It should be easy to patch if a custom Lua executable is
> > an option to you.
>
> Thanks, I thought someone might say that. Shame really, it'd be a
> nice feature to have in standard Lua (mind you this is the first time
> it's come up in a good few years of using Lua)
luacov should wrap os.exit() and dump that stats before calling the normal
os.exit().
I don't know much about how luacov is implemented, but if they have a function
that can be called from Lua to dump the stats, then you can write a custom
os.exit() wrapper:
local exit=os.exit
os.exit = function(...)
luacov.dumpstats() -- I don't know if a funciton like this exists.
exit(...)
end
--
Robert G. Jakabosky