Re: How to timeout a running function??

["Leo Razoumov" <slonik.az@...>]

On 10/30/06, Luiz Henrique de Figueiredo <lhf@tecgraf.puc-rio.br> wrote:
> For Lua functions, you can set a count hook and call error for there.
> For C functions, you need a real timer. Even then, you need to be careful
> how you interrupt Lua. See how lua.c does it or my lalarm. --lhf

Luiz,
thanks a lot for your reply. lalarm seems to address my problem for C functions.
On the other hand I do not see how setting count hook would help to
time-out a Lua function. According to Lua manual count hook cannot
count time. It counts instructions, lines of code, function
invocations/returns. How would  count hook help me if my foo()
functions is blocking inside?

function foo(key)
 local res= get_resource() -- can possible block for long time
 return  res:lookup( key)
end

Can I use lalarm to break out from Lua function? Would setjmp/longjmp
used in alarm handler leave Lua in inconsistent state?

--Leo--