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Was trying to make a/b return both integer divident and modulo, but it seems these metamethod tricks cannot return more than the return values they 'normally' would. Is this by chance of by design? I think it would be neat to have integer division provide both:

	a= b/c		-- just divident, if either 'b', 'c' or both are int32 userdata
	a,d= b/c	-- getting both divident & modulo at once.