division overload

[Asko Kauppi <asko.kauppi@...>]

Was trying to make a/b return both integer divident and modulo, but it 
seems these metamethod tricks cannot return more than the return values 
they 'normally' would.  Is this by chance of by design?  I think it 
would be neat to have integer division provide both:

	a= b/c		-- just divident, if either 'b', 'c' or both are int32 userdata
	a,d= b/c	-- getting both divident & modulo at once.

-ak