Re: [FUN] CodeGolf: solve equation x^x=C

[Philippe Verdy <verdy_p@...>]

Le jeu. 27 juin 2019 à 18:30, Philippe Verdy <verdy_p@wanadoo.fr> a écrit :

i.e. it's enough to pass to the recursion call the value x^x*(1+(log2(x)*x<1024 and 1 or 0))

correction: pass the value x^x*(x*log2 x<1024 and 1 or 0)

So you get an anwer:

f f f f f f(x^x*(x*log2 x<1024 and 1 or 2))

I think that (x*log2 x<1024 and 1 or 2) can be implemented using an integer division to remove the "and"/"or":

(x*math.log2 x div 512) 

And we get something like:

f f f f f f(x^x*(x*math.log2 x div 512))

function f(x) return

x^x*(x*math.log2 x div 512)

end

and to get the value just call "f f f f f f x"