Re: how to translate lua pattern "(.*)and(.*)" with lpeg re ?

[albertmcchan <albertmcchan@...>]

i added re.upto function in lpeg re.lua

function re.upto(what, greedy)
     local fmt = string.format
     local c = fmt('(!(%s).)', what)
     if greedy then c = fmt('((%s) !(%s* !.) / %s+)', what, c, c) end
     return fmt({%s*} (%s) ', c, what)
end

text = 'this and that and whatever'

= re.match(text, re.upto( " 'and' " ) .. "{.*}")             -- non-greedy match
this
that and whatever

= re.match(text, re.upto( "[aA][nN][dD]" ) .. "{.*}")   -- non-greedy case-insensitive
this
that and whatever

= re.match(text, re.upto( " 'and' ", true) .. "{.*}")      -- greedy match
this and that
whatever

plain lpeg upto function if interested:

http://www.gammon.com.au/forum/bbshowpost.php?id=14149&page=2