Re: Rounding a number to integer

[Roberto Ierusalimschy <roberto@...>]

> > Another try :-)
> >
> > -- unbiased rounding
> > function round (x)
> >   if math.floor(x) == x then return x
> >   else
> >     return math.floor((x % 2.0 == 0.5) and x or x + 0.5)
> >   end
> > end
> >
> 
> round(0.0) gives float result 0.0 instead of integer 0

Is this in the "rules"?  :-) If so, it seems easy to fix:

function round (x)
  local fx = math.floor(x)
  if (fx == x) or (x % 2.0 == 0.5) then
    return fx
  else
    return math.floor(x + 0.5)
  end
end

-- Roberto