Re: Rounding a number to integer

[Roberto Ierusalimschy <roberto@...>]

> On Sun, Jul 31, 2016 at 9:33 PM, Roberto Ierusalimschy <
> roberto@inf.puc-rio.br> wrote:
> 
> > What about this one?
> >
> > function round (x)
> >   return math.floor((x % 2.0 == 0.5) and x or x + 0.5)
> > end
> >
> 
> > (2^52+1)|0, round(2^52+1)
> 4503599627370497    4503599627370498

Another try :-)

-- unbiased rounding
function round (x)
  if math.floor(x) == x then return x
  else
    return math.floor((x % 2.0 == 0.5) and x or x + 0.5)
  end
end

-- Roberto