Re: luaL_loadstring error with dumped chunk

[Sean Conner <sean@...>]

It was thus said that the Great Victor Bombi once stated:
> Once I had the same problem.
> Solution was given in the list:
> use luaL_loadbuffer instead of  luaL_loadstring

  What he said.

  Another approach to use, instead of using lua_dump() is to use
string.dump().  A "proof-of-concept" (Lua 5.1, but should be easily
adaptable to 5.2 if that's what you are using):

#include <stdlib.h>
    
#include <lua.h>
#include <lualib.h>
#include <lauxlib.h>
 
int main(int argc,char *argv[])
{
  lua_State  *L;
  lua_State  *L2;
  const char *origcode;
  char       *copy;
  size_t      size;
  int         rc;  
  
  if (argc == 1)
    return EXIT_FAILURE;
  
  L = luaL_newstate();
  luaL_openlibs(L);   
  
  lua_settop(L,0);

  /* luaL_loadstring() works here as well ... */
  
  luaL_loadfile(L,argv[1]);     /* -- func */
  lua_getglobal(L,"string");    /* -- func tab-string */
  lua_getfield(L,2,"dump");     /* -- func tab-string f-dump */
  lua_pushvalue(L,1);           /* -- func tab-string f-dump func */
  lua_call(L,1,1);              /* -- func tab-string bin-func */

  origcode = luaL_checklstring(L,3,&size);
  copy     = malloc(size);
  memcpy(copy,origcode,size);
  lua_pop(L,2);                 /* -- func */
  
  rc = lua_pcall(L,0,LUA_MULTRET,0);
  if (rc != 0)
  {
    const char *err = lua_tostring(L,-1);
    fprintf(stderr,"lua_pcall(L) = %s\n",err);
    return EXIT_FAILURE;
  }
   
  L2 = luaL_newstate();
  luaL_openlibs(L2);   
  
  rc = luaL_loadbuffer(L2,copy,size,"copy");
  if (rc != 0)
  {
    fprintf(stderr,"luaL_loadstring(L2) = %d\n",rc);
    return EXIT_FAILURE;
  }
   
  rc = lua_pcall(L2,0,LUA_MULTRET,0);
  if (rc != 0)
  {
    const char *err = lua_tostring(L2,-1);
    fprintf(stderr,"lua_pcall(L2) = %s\n",err);
    return EXIT_FAILURE;
  }
   
  lua_close(L2);
  lua_close(L); 
  return EXIT_SUCCESS;
}

  -spc (string.dump() is there ... might as well use it)