|
On 2014/8/8 11:24, albert_200200 wrote:
In python's Mock module, there's autospeccing thing, you can let
the mock object
behave exactly like the object you mocked, like you should have
the same args signature.
I don't know if there's the same thing in lemock.
Now take such situation.
public.lua
---------------------------------------------------
local M = {}
function M.add_internal(a, b)
return a+b
--add_internal may call some global function, so I should mock
add_internal
end
function M.add(a, b)
return M.add_internal(a, b)
end
return M
Then I need to test public.add function, because add_internal may
could call some global function,
I'd like to mock add_internal function.
test.lua
---------------------------------------------------
require("lunit")
lunit.setprivfenv()
lunit.import "assertions"
lunit.import "checks"
require("lemock")
local ut = lunit.TestCase("public.add function test")
function ut:test()
local public = require("public")
mc = lemock.controller()
mock_add_internal = mc:mock()
package.loaded.public.add_internal = mock_add_internal
mock_add_internal(2, 3); mc:returns(5)
mc:replay()
local result = public.add(2, 3)
assert_equal(5, result)
mc:verify()
end
lunit.run()
Now take such situation, I modify public.add_internal'code as
below:
public.lua
---------------------------------------------------
local M = {}
function M.add_internal(a, b, c)
return a+b+c
--add_internal may call some global function, so I should
mock add_internal
end
function M.add(a, b)
return M.add_internal(a, b)
end
return M
But I leave the test.lua unmodified, the unittest would pass too.
Is there a way to solve this problem?
Could someone know how to solve this problem? It really bothers me
for a while.
|
