Re: catching divide by zero

[Bezobiuk Volodymyr <dedoogun@...>]

and looks like second infinity was bigger than first one... as it returns '-nan' not just 'nan' :)

On Thu, Dec 19, 2013 at 9:03 PM, Coda Highland <chighland@gmail.com> wrote:

On Thu, Dec 19, 2013 at 9:59 AM, Luiz Henrique de Figueiredo
<lhf@tecgraf.puc-rio.br> wrote:
>> Until someone swaps out the math library for one that supports complex
>> numbers...
>
> Ok, so try
>         local nan_value = 1e999999-1e999999
>

Infinity minus infinity. Indeterminate form. I like it!

/s/ Adam