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- Subject: Re: function call in table with reference
- From: Philipp Janda <siffiejoe@...>
- Date: Sun, 25 Aug 2013 17:13:00 +0200
Am 25.08.2013 15:50 schröbte Philipp Kraus:
On 2013-08-23 16:45:09 +0000, Philipp Kraus said:
I can do x.test() or x:test(), both calls result nil.
The parameter "self" is always nil, so imho I have a wrong definition
in my metatable
[...]
__index = function(self, key, ...)
The __index metamethod gets called with only two arguments (self and
key), so your vararg list is always empty. So ...
local lxReturn = self.__instancedata[key]
if type(lxReturn) == "function" then
return lxReturn( self.__instancedata, ... )
... this function is always called with exactly one argument
(self.__instancedata). All other explicit parameters will be nil, and a
vararg parameter list will be empty.
end
[...]
I run this with
local myClass = class("MyClass")
function myClass:constructor( self, pxID )
self.id = pxID
end
function myclass:test(self, ...)
If you define your methods using the colon operator you already get an
implicit self parameter, so your function definition is equivalent to:
function myclass.test( self, self, ... )
where the second self parameter shadows the first one. As stated above,
the second self argument will always be nil, and the vararg parameter
list will be empty. The constructor function has a similar problem ...
print(self)
end
local x = myClass( 123 )
x:test()
the print(self) results always nil. the __call and __gc works well also
the __newindex, but the __index does not work
Using __index for method calling will not work, because then you can't
pass arguments to the method. It must always be a two-step process,
where you return something callable from your __index metamethod.
Remember that `x:test()` is the same as `x[ "test" ]( x )` and you are
trying to do all the work in `x[ "test" ]` ...
Thanks for help
Phil
HTH,
Philipp