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> This string causes "malformed number" error:
> print(64..'KB')
> It seems that lexer does not know that two dots are never contained in
> numerical constant.
> IMHO, correct parsing of numerical constant should stop before
> concatenation operator.

Scanners usually know very little. They seldom do backtracking or know
about grammar. Most of them operate on the "longest sequence" rule.  By
this rule, the "correct parsing" of the string |64..'KB'| would be |64.|
(a number), |.| (the dot operator), and |'KB'| (a literal string).

That would give you an error anyway, only a different one.

-- Roberto