Re: Shorten long boolean IF conditions?

[Dirk Laurie <dpl@...>]

On Fri, Aug 19, 2011 at 09:37:49AM +0200, Gregory Bonik wrote:
> Daniel Hertrich wrote:
> > I'd like to shorten an if condition such as:
> 
> > if strCustomPropertyValue == "inbox" or strCustomPropertyValue ==
> > "today" or strCustomPropertyValue == "thisweek" or
> > strCustomPropertyValue == "thismonth" or strCustomPropertyValue ==
> > "thisyear" or strCustomPropertyValue == "later" or
> > strCustomPropertyValue == "someday" or strCustomPropertyValue ==
> > "archive"  or strCustomPropertyValue == "otherpersons"  then
> > ...
> > end
> 
> An alternative to the solution with tables is a vararg function:
> 
> function is_one_of(value, ...)
>     for k, v in ipairs(arg) do
>         if v == value then return true end
>     end
> end
> 
That version works in Lua 5.0 and Lua 5.1, but not Lua 5.2.

This one works in Lua 5.1 and Lua 5.2, but not Lua 5.0.

    function is_one_of(value, ...)
        for k, v in ipairs{...} do
            if v == value then return true end
        end
    end

Dirk