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On Tue, Feb 15, 2011 at 4:25 AM, steve donovan
<steve.j.donovan@gmail.com> wrote:
> $(AL 's.y') = $(VL 'v_')
>
> which expands to
>
> s.y[0],s.y[1] = v_0,y_1

wouldn't that be :

s.y[0],s.y[1] = v_0,v_1

?

-- 
Javier