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On 3/6/10, Roberto Ierusalimschy <> wrote:
>> If s:sub(5,4) is valid then s:sub(1,0) should be valid too.
> Sure. s:sub(1,n) is the prefix of 's' with length 'n', so zero must be
> a valid index to allow the empty prefix. zero is not negative, so it
> counts from the beginning.
> -- Roberto

It's just that since s:sub(2,n) doesn't mean "the substring of 's'
with length 'n' starting at the second position of 's'", it just feels
that your point is a happy coincidence rather than a particular case
of a rule.

I feel like I managed to misuse the "principle of [Roberto's] least
surprise" and break list etiquette.