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Paul Moore wrote:
In (some versions) of regular expression syntax, the construct x{m,n}
matches between m and n copies of the pattern x. So, for example,
\d{3,5} matches 3-5 digits. However, I can't find a precise equivalent
in lpeg - it appears that the only way is to repeat the pattern m
times, then add ( the pattern ^ - (n-m) ). Is that the case?
P^n - P^(m+1)
e.g.
d=lpeg.R('09')
p=d^2 - d^5
print(p:match'1') -- nil
print(p:match'12') -- 3
print(p:match'12345') --nil