Re: Regular expression for matching lines

[Eike Decker <eike@...>]

Zitat von "Thomas Harning Jr." <harningt@gmail.com>:

> On 7/26/07, Eike Decker <eike@cube3d.de> wrote:
> > Hi
> >
> > I am trying to find a regular expression that matches each line of an
> input
> > string but cannot find an expression that needs no additional checks. What
> I
> > have tried so far:
> >
> > for line in str:gmatch("[^\n]+") do
> > matches not empty lines
> >
> > for line in str:gmatch("([^\n]*)\n?") do
> > matches every line correctly BUT returns an empty string after the last
> > character, i.e.
> > "123" results in
> > line = "123"
> > line = ""
> >
> > I cannot get rid of the last match, so I wonder if there is an elegant
> > expression to match every line correctly, even empty lines and without
> adding
> > "virtual" lines.
> How about this this...  it will give you every line...
> 
> str:gmatch("([^\n]*)")
> 
> No need to make it try to match the newline char...  Not sure how it
> handles the end-of-string case however...
> -- 
> Thomas Harning Jr.
> 


Won't work (tried it out) for the string

"1\n2\n345\n\n6789"
it will produce
1

2

345


6789

Every linebreak is captured as a zerolength string.

Eike