Re: Varargs in function definitions

[roberto@... (Roberto Ierusalimschy)]

> One such change that might be made (the Lua team can say how
> likely this is) is the removal of the prohibition on using
> the vararg expression as an upvalue.

Not likely. This would imply the creation of another kind of upvalues;
actually up-non-values, as '...' is not a (regular) value ;)

-- Roberto