Re: '...' is a variable,who can explain

[Daniel Silverstone <dsilvers@...>]

On Fri, 2007-01-12 at 17:00 +1100, David Burgess wrote:
> It does raise the question of whether
>   type(...)
> should return a value?

I believe it should.

After all, f(...) means "call the function 'f' passing it the unpacked,
unclaimed argument set" (approximately)

so type(...) would return the type of the first unclaimed argument in a
new-style vararg function.

D.

-- 
Daniel Silverstone                         http://www.digital-scurf.org/
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