Re: '...' is a variable,who can explain

["jason zhang" <jzhang@...>]

function ::= function funcbody
funcbody ::= `(´ [parlist1] `)´ block end

parlist1 ::= namelist [`,´ `...´] | `...´

 

... means vararg function.

 

----- Original Message -----

From: wj

To: lua@bazar2.conectiva.com.br

Sent: Friday, January 12, 2007 1:24 PM

Subject: '...' is a variable,who can explain

look at this code:

 

--codes begin

 

function joinFunc(f1,f2)
  return function (...)
           return f1(f2(...)) --...treated as a variable! is it maze!
   end

end

 

f1 = joinFunc(print,math.abs)

 

f1(-2) --out:2

 

--codes end

 

why the