Re[2]: Need help building a regexp pattern

[Theodor-Iulian Ciobanu <tciobanu@...>]

Hello Denis,

Yes, that helps. Thanks. Not to make it a little bit more difficult, what about strings like these:

[a] [aaa...] aaaaaaaa...
or
[aaa] a.....

Just like before, but this time the first two captuers are ensclosed between [], so I'd have to take them into account as well. Is there a way do this in as single match, or should I use "(.*)%[(.+)%](.*)" and extract the character I want from the first capture, if it's not nil?

Friday, October 27, 2006, 10:30:58 AM, you wrote:

DP> Hi Theodor!

DP> If I understand you correctly, main goal is to eliminate second call of
DP> string.find(). Although you didn't provide a sample of your strings I
DP> hope my test sample will be helpful. 

DP> Main idea is to use for first capture "(.*)" instead of "(.)". And, in
DP> case of first type of string you'll receive a symbol and in case of
DP> second type it will be an empty string. Empty string may be easity
DP> converted to nil, if it required.

DP> Maybe there's a better solution, which will give you exactly you want
DP> (nil for the first capture), but at a first sight I suppose my version
DP> completely fits your needs.

DP> WBR, Denis

DP> -----------------------
DP> m1 = "(.)(.)(.)"
DP> m2 = "(.*)(.)(.)"
DP> str1 = "ABC"
DP> str2 = "BC"

DP> _, _, cap1, cap2, cap3 = string.find( str1, m1 )
DP> print( cap1, cap2, cap3 )
DP> _, _, cap1, cap2, cap3 = string.find( str2, m1 )
DP> if cap1 == "" then cap1 = nil end
DP> print( cap1, cap2, cap3 )
DP> ---------------------

-- 
Theodor-Iulian Ciobanu
jr Virus Researcher

e-mail: tciobanu@bitdefender.com

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