Re: How to read thru a script file from C a line at a time.

["Jason Zhang" <jzhang@...>]

The interactive mode of the Lua interpreter solve the same problem.

----- Original Message ----- 
From: "Edward Mitchell" <emitchell@ieee.org>
To: <lua@bazar2.conectiva.com.br>
Sent: Tuesday, October 17, 2006 9:38 PM
Subject: Re: How to read thru a script file from C a line at a time.


> 
> "Jason Zhang" <jzhang@sunrisetelecom.com.cn> wrote in message 
> news:014901c6f22d$efcb0e30$a300000a@LAPTOPSRC...
>> You can have a look at the lua.c.
>>
> I'm not sure where to look. I would expect a loop like:
> 
>    while(templateFile) {
>        templateFile.getline(buff, BUFSIZ);
>        // ?? debug echo to the console
>        fprintf(stdout, "%s\n", buff);
>        // loop until there is a complete syntax element
>        while(!luaL_loadbuffer(L, buff, strlen(buff), "Line") {
>            templateFile.getline(buff, BUFSIZ);
>        }
>        // execute the complete chunk on the stack
>        int iError = lua_pcall(L, 0, 0, 0);
>        if(iError) {
>            ...
>            break;
>        }
>    }
> 
> where I would keep on calling luaL_loadbuffer(...) until the syntax analyser 
> said that the last syntax element was complete.  luaL_loadbuffer(...) seems 
> to only return
> 
> As far as I can see, there's nothing like this in lua.c. It seems that 
> lua_load(...) (or luaL_loadbuffer) should return an status code that implies 
> "Needs more input."
> 
> 
> 
>