Re: boolean operators

[Wim Couwenberg <w.couwenberg@...>]

> In that context, once the
> decision is made to implement %, which I have no problems with, it
> seems reasonable to me to implement the other half of that operation,
> euclidean division.

Would it be terribly confusing if in fact // was a divmod operator?  In 
pseudo code:

operator //(x, y)
    return math.floor(x/y), x%y
end

Their computations are often intertwined anyway, I suspect...

--
Wim