Re: boolean operators

[Rici Lake <lua@...>]

On 21-Sep-06, at 5:01 PM, David Jones wrote:

> Le 21 Sep 2006 à 21:28, Rici Lake a écrit :
>
> > Regardless of bitwise operators, I would vote strongly in favour
> > of an integer divide operator, to go along with 5.1's remainder (%)
> > operator. At the risk of alienating C++ programmers, I'd suggest
> > that integer divide be spelled "//". It's precise definition
> > would be:  a // b ==>  (a - a%b) / b
>
> Lispers would ask for floor, ceiling, truncate, and round as well.  
> Funny how no-one ever wants round-away-from 0, could be called 
> "inflate" perhaps?

In Lua, % is defined as "the remainder of the division that rounds the 
quotient towards minus infinity".


Consequently:

floor: a // 1
ceiling: -(a // -1)
round: (a + .5) // 1

(I don't have a good one for truncate, without using abs and sign).

Still, I think // is pretty generally useful.