% operator (Re: boolean operators)

[askok@...]

The way % is defined, it's rather useful for controlling 
reported accuracy of numbers, not only for integers.

I think Roberto et.al. did a jolly good job in the way 
that operator came in; it's probably just veeeery 
underutilized at the moment. :)

-asko

(maybe because it's not emphasized in the online 
documentation; I think I've seen discussion on the use of 
% somewhere, maybe PIL book, then?

Ref.manual simply states this: "Modulo is defined as
     a % b == a - math.floor(a/b)*b
That is, it is the remainder of a division that rounds the 
quotient towards minus infinity."

In practise, 123.45 % 0.1 = 0.05 (or... so it SHOULD be :)

> print( 123.45 % 0.1 )
0.049999999999996

Now, when can we get the BCD number implementation?  :P
)



On Wed, 27 Sep 2006 06:16:31 -0400
 Glenn Maynard <glenn@zewt.org> wrote:
> On Thu, Sep 21, 2006 at 06:53:26PM -0500, Rici Lake 
> wrote:
> > In Lua, % is defined as "the remainder of the division 
> > that rounds the 
> > quotient towards minus infinity".
>
> At the cost of being repetitive, is there a reason for 
> wanting this, other
> than performance (discussed elsewhere)?  It just seems 
> like there's a whole
> lot of calls for more and more operators in Lua these 
> days--on the tail of
> someone asking for a table append operator comes the 
> bitwise operator
> thread, and then this.  With an operator for every 
> operation that "inline"
> would be useful for in C, there will be a lot of 
> operators.
>
> --
> Glenn Maynard