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- Subject: Re: How to spawn a windows process without blocking?
- From: David Morris-Oliveros <david.morrisoliveros@...>
- Date: Mon, 06 Mar 2006 12:56:42 +1100
You can call "start" first:
os.execute('start "window title" "notepad.exe"')
The problem with start.exe is that the first quoted parameter is the
title of the window, so, doing this:
os.execute('start "c:\\full path\\to\\notepad.exe"')
Will open up a console window with the title bar as "c:\\full
path\\to\\notepad.exe", so, you have to put whatever infront of it, it
can just this:
os.execute('start "blah" "c:\\full path\\to\\notepad.exe"')
// David Morris-Oliveros
// Camera & Lua Coder
Yuanming Chen wrote:
Recently I started to use LUA to write simple scripts to launch
windows executables. But I noticed that when I call
os.execute("notepad.exe") to spawn notepad application, the execution
thread is blocked till one closes the notepad. Is there a way to
execute the window executable without blocking? In my project, I don't
care about whether the window executable is started correctly or not.
Thanks for any thoughts on this.