RE: Lua 5 iterator question

["Bilyk, Alex" <ABilyk@...>]

Title: Lua 5 iterator question

It's more like this

 

----------- CUT HERE -----------------------------

function lineIterator(str)
   local pos
   local function lineIterate()
           if not pos then
              pos = 0
           end
           local s1 = string.find(str, "\n", pos, true)
           local line
           if not s1 then
              pos = nil
           else
              line = string.sub(str, pos, s1-1)
              pos = s1 + 1
           end
           return line
   end
   return lineIterate  
end

 

s = [[
***hello
***this
***is
***a
***string
]]

s1 = [[
   ###
   @@@
]]

 

for line in lineIterator(s) do
   print(line)
   for line2 in lineIterator(s1) do

       print(line2)

   end
end

----------- CUT HERE -----------------------------

 

I am sure this could be more optimal as the iterator creates new function on every iteration.

Alex

-----Original Message-----
From: Stewart, Joseph [mailto:Joseph.Stewart@sciatl.com]
Sent: Thursday, February 12, 2004 7:06 AM
To: 'Lua list'
Subject: Lua 5 iterator question

Hello all,

I've read the lua 5 documentation and looked at the iterator tutorial, but I'm still stumped on how to create an interator function that will step through a string a line at a time.

Here's the code I've come up with so far (from memory, the code is a home):

function lineIterate(state,n)
        local s1
        s1 = string.find(n, "\n", state)
        if not s1 then return nil end
        return s1+1, string.sub(n, state, s1)
end

s = [[hello
this
is
a
string]]

for i,v in lineIterate(i, s) do print(v) end

Am I way off base? Thanks for all suggestions!
-joe

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