Re: Lua5.0 new "For" question

[Eero Pajarre <epajarre@...>]

Björn De Meyer wrote:
> you can still say
>
> function fie()
>      local x=123
>      f = function() return %x end
>      x=456
>      print(f())
> end
>
> But that one seems to behave exactly the same as when not
> using the %, namely it will print 456. Because of the 
> lexical scoping the x in the anonymous function is the 
> local x of fie(). The value of x is only "taken" 
> when f() is called.


Looks like % is just accepted for compatibility,
but otherwise ignored (except the global upvalue message)

So your example creates a closure with or without the "%".
See:

function fie()
     local x=789
     f = function() return x end --global f
     x=123
end

fie() -- call function which creates function f

print(f()) -- prints 123

x=456

print(f()) -- still prints 123

		Eero