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Hi all,

Having painted myself into a corner, I needed a script which would
look up the full path of a Lua module and run it as the main script.

So if test.lua is on the Lua module path, and is

for i = 1,#arg do print(arg[i]) end


$ lua lenv.lua test one two three

But what I get is, on both Windows and Ubuntu:

$ lua lenv.lua test one two three

Here's the full script (the concept at least might be useful/interesting)

It does work with markdown.lua, which is distributed as a module but
often gets used as a program.

-- lenv.lua --------------------------------------------
local dir_separator = package.config:sub(1,1)

local function searchpath (mod,path)  -- Lua 5.2 provides us this
directly, of course
  mod = mod:gsub('%.',dir_separator)
  for m in path:gmatch('[^;]+') do
    local nm = m:gsub('?',mod)
    local f =,'r')
    if f then f:close(); return nm end

local function package_path(mod)
    mod = mod:gsub('%.',dir_separator)
    local res = searchpath(mod,package.path)
    if res then return res end
    return nil,'cannot find module on path'

local modpath = package_path(arg[1])
if not modpath then
   return print ('cannot find module '..arg[1])

table.remove(arg,1)  -- the module name
arg[0] = modpath  -- this is now our program (some modules check this)
local res,err = dofile(modpath)
if not res then print(err) end

Note that printing out the array items in arg after the modification
does print what I expect, except that the dofile() invocation adds the
extra nil, which some scripts may take exception to.

I suppose I could do an os.execute() at this point, but I'm curious
why there is an extra item in arg when the main script is run in

(The particular corner problem is similar to the markdown case;
lake.lua would get distributed as a module by LuaRocks, but is usually
invoked as a program, and I want to avoid an install script.)

steve d.