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Le Tue, 17 Nov 2009 08:31:39 -0500,
Jim Pryor <> stated:

> On Tue, Nov 17, 2009 at 08:23:24AM -0500, Jim Pryor wrote:
> > If you only have one
> > loop---it doesn't matter how many iteration steps it involves---then
> > only one object is getting created and so the garbage collection costs
> > will be negligible. You're basically just testing here how much it slows
> > down a function to lookup its upvalues. And the answer is, hardly any
> > slowdown.
> Sorry, I looked at your code again. I was wrong. You're not just running
> through a single loop for each case, you are correctly creating the loop
> multiple times.
> However, your testing code doesn't do anything to manage when the
> garbage collection costs are incurred. So for that reason you can't rely
> on it for insight into the performance costs at issue here.
> It would be better to insert a 
>     collectgarbage("collect")
> before the
>     print(os.time()-t0)
> in each block.

Thank you for the hint. (Next time I need to time something, I'll probably think at including GC if relevant).

* la vita e estrany *