• Subject: Re: comparing binary numbers with strings
• Date: Sat, 27 Oct 2007 13:55:27 +1300

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how can adding 2 numbers, converting it to a string, then pattern matching it to "2" do anything useful? string.match returns either a substring or nil. So, you'll get something non-nil if the result of the addition contains the digit 2 in decimal. That's certainly not what was requested?
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e.g. take 10000 and 00100, no matching bits but

16 + 4 = 20, which contains "2"

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without bit-wise operators in lua (e.g. XOR), you're going to need to go through the digits one at a time I'm afraid...
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Merick wrote:
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```Shmuel Zeigerman wrote:
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```Merick wrote:
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I was wondering if there was any way - other than using a for loop to iterate through each character - to use the string library to compare two strings with representations of binary numbers and tell whether or not any of the 1's in the strings are in the same position?
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```
Something like compare("11100", "00011") would return false and compare("11100","00111") would return true
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```
```
function compare(a,b)
a = tostring(tonumber(a) + tonumber(b))
return a:match"2"
end

```
```Dangit, that's so simple I can't believe I didn't think of it myself!

Thanks
```
```
--
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