Re: Strange string.format result

[bil til <biltil52@...>]

PS: The following also might be interesting:
> do
>> function Test() return 3, 5 end
>> s= string.format( "%d %d", Test(), 4)
>> end
> s
3 4

... so it looks like the '...' of string.format somehow keeps only the
first return value of Test, except if Test function is the last
parameter... . Is this normal?

(I thought, that for such "further parameter stripping" it would be
required to specify this explicitely by brackets like in s=
string.format( "%d %d", (Test()), 4)? (this gives the same as above,
in this case it is clear to me...).

Am Fr., 25. Nov. 2022 um 23:46 Uhr schrieb bil til <biltil52@gmail.com>:
>
> If I do the following in Lua 5.4:
> > do
> >> function Test() return 3, 5 end
> >> s= string.format( "%d %d %d", 4, Test())
> >> end
> > s
> 4 3 5
> ... this is as expected...
>
> > do
> >> function Test() return 3, 5 end
> >> s= string.format( "%d %d %d", Test(), 4)
> >> end
> stdin:3: bad argument #4 to 'format' (no value)
> stack traceback:
>         [C]: in function 'string.format'
>         stdin:3: in main chunk
>         [C]: in ?
> ... this somehow does NOT work as I would expect... (I would expect
> that s now is '3 5 4')
>
> (if I debug with breakpoint in str_format, then the top of stack ( int
> top = lua_gettop(L);) is only 3 in this last case... in first case it
> is 4 as expected.... .
>
> Is this some error of Lua, or do I miss here something?