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On Sun, Jun 7, 2020 at 5:49 AM Baozeng wrote:
The register is represented  by `A`,  which is still 8 bits.  I have not changed it.  Only `B` is changed from 9 bits to 8 bits. and `C` is changed from 9 bits to 8 bits. 

RK(B) encodes either register or constant (256 registers and 256 constants, 9 bits in total)
If your B is 8 bits then only 128 registers are addressable?