Re: [proposal] require resources

["Soni \"They/Them\" L." <fakedme@...>]

If you had:

LUA_PATH/foo/init.lua
LUA_PATH/foo/bar/init.lua
LUA_PATH/foo/bar/res.txt

then require("foo.bar", "res.txt") would get you the contents of 
LUA_PATH/foo/bar/res.txt

HOWEVER this would only apply to the default loaders. what I mean by 
that is that one could make a zip file loader and then you can have your 
whole module (and submodules) as a zip file instead.

foo.zip
| init.lua
| bar/init.lua
| bar/res.txt

which is a lot harder than opening a file in LUA_PATH.

On 2020-01-19 9:37 p.m., Egor Skriptunoff wrote:
> On Mon, Jan 20, 2020 at 3:25 AM Soni "They/Them" L. wrote:
>
>     require("foo.bar", "res.txt") would look for "res.txt" as a file in
>     module "foo.bar"
>
>
> What value is expected to be returned by require("foo.bar", "res.txt")?
>
> Why not using a function for the same task?
> local res = require("foo.bar").get_resource()