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I wrote this C function to print the names of all local variables:

    void dumplocals(lua_State *L) {

        lua_Debug ar;
        int level = 0, i;
        const char *name;

        if(lua_getstack(L, level, &ar) == 0) {
            printf("Error\n");
            return;
        }

        i = 0;
        while((name = lua_getlocal(L, &ar, i + 1)) != NULL) {
            printf("%s\n", name);
            lua_pop(L, 1);
            i++;
        }
    } 

And this is the Lua code:

    do
       local a,b,c=1,2,3
       print(a,b,c)
       testfunc()
    end

Note that testfunc() is a C function. Now I'd like to print the names of all local variables when testfunc() returns. That's why I have added a call to dumplocals() to lvm.c/luaV_execute() in the OP_CALL/OP_TAILCALL branch as follows:

        firstResult = luaD_precall(L, ra);
        if (firstResult) {
          if (firstResult > L->top) {  /* yield? */
            lua_assert(L->ci->state == (CI_C | CI_YIELD));
            (L->ci - 1)->u.l.savedpc = pc;
            (L->ci - 1)->state = CI_SAVEDPC;
            return NULL;
          }
          /* it was a C function (`precall' called it); adjust results */
          luaD_poscall(L, nresults, firstResult);
          if (nresults >= 0) L->top = L->ci->top;

          // !!! THIS IS THE ONLY LINE I ADDED !!!
          dumplocals(L);
        } 

Note that I'm still on Lua 5.0.

Now I'd expect dumplocals() to print

    a
    b
    c

But it doesn't do that. Instead, lua_getlocal() in dumplocals() always returns NULL although there should be three local variables a,b,c. So I don't really understand why this doesn't work. Can anybody explain?

-- 
Best regards,
 Andreas Falkenhahn                          mailto:andreas@falkenhahn.com