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> On Jun 28, 2019, at 6:42 AM, Xavier Wang <weasley.wx@gmail.com> wrote: > > btw, why (ln(C)+x)/(ln(x)+1) can be simplify to math.log(C,x)? x^x = c x ln(x) = ln(c) x = ln(c)/ln(x) = log(c,x) Above iterated solution converge only if denominator ln(x) > 1 x > e c = x^x > e^e ~ 15.155 < 15.5