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It was thus said that the Great pygy79@gmail.com once stated:
> Actually, I read i too fastt :-)
> 
> Still, the folding capture would also handle counting arbitrary
> captures more cleanly:
> 
>     cnt = Cf(Cc(0) * C(1)^0 , function(total) return total +1  end)

  I think *that* would work.

  -spc