Re: how to translate lua pattern "(.*)and(.*)" with lpeg re ?

[Albert Chan <albertmcchan@...>]

I think it is just luck that xpattern work for my previous post.

After reading xpattern.lua a bit, it does NOT do backtracking.

So, previous xpattern work only because it had an 'and' anchor.

-- this will *NOT* work, X'(.*)' consumed everything -> always fail

p1 = X'(.*)' * (X'possibly' + 'likely' + 'definitely') * X'%s+(.*)'