• Subject: Re: how to translate lua pattern "(.*)and(.*)" with lpeg re ?
• From: Dirk Laurie <dirk.laurie@...>
• Date: Fri, 16 Feb 2018 16:50:53 +0200

```2018-02-16 16:09 GMT+02:00 albertmcchan <albertmcchan@yahoo.com>:
>
> On Feb 16, 2018, at 8:04 AM, Dirk Laurie <dirk.laurie@gmail.com> wrote:
>
>> 2018-02-16 14:13 GMT+02:00 albertmcchan <albertmcchan@yahoo.com>:
>>> I post this about a month ago.  I've found a simple lpeg re pattern for above
>>>
>>> It can handle "repeated" separactor too, say, "(.*)andand(.*) too.
>>>
>>> pat = re.compile( "{ (.(g <- &%z / .g))* } %z {.*}", { z = 'and' } )
>>>
>>> note: the loop never match the first position, but it is ok
>>> the second %z take care of of text with %z up front.
>>
>> Just remind me ... since `lpeg` and `re` are packages you need
>> to load into Lua, and standard Lua comes with a string library,
>> why on earth would you want to do things in `re` that Lua can
>> already do very well without it?
>>
>
> you are right.
>
> If all I wanted were captures of "(.*)and(.*)", I would use string.match
> I had picked the simple pattern to learn about lpeg matching.
>
> But ... what if z = re.compile " 'and' %s+ ('possibly' / 'likely' / 'definitely') %s+ " ?
> or, possibly even more complicated ?
>
> Above lpeg re pattern can handle it

LPeg without `re` handles it too.

C, P = lpeg.C, lpeg.P
kw = P'possibly' + 'likely' + 'definitely'
(C((1-kw)^0) * kw * (P(-1)/''+C(P(1)^0)))

```

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