Re: how to translate lua pattern "(.*)and(.*)" with lpeg re ?

[Nick Gammon <nick@...>]

On 21/01/18 13:18, Sean Conner wrote:
>    You might want to read the thread starting here:
>
> 	http://lua-users.org/lists/lua-l/2017-10/msg00126.html
>
> I think relevant to your problem is this post:
>
> 	http://lua-users.org/lists/lua-l/2017-10/msg00140.html

OK, that was very helpful, thanks Sean.

I worked it out with this grammar:

require "re"

target = "foo and bar and whatever"

c = re.compile [[
   parse     <- {| {noDelim} lastDelim |}  -- look for all up to the last delimiter followed by the last part
   delim     <- 'and'                      -- our delimiter
   noDelim   <- (!lastDelim .)*            -- zero or more characters without the last delimiter
   lastDelim <- delim {(!delim .)*} !.     -- the delimiter without any more delimiters and then end of subject
]]

result = lpeg.match (c, target)

for k, v in ipairs (result) do
  print (k, v)
end -- for


Output:

1 foo and bar
2  whatever


- Nick