Re: How does Lua parse newlines?

["Soni L." <fakedme@...>]

On 2017-10-14 12:34 PM, Soni L. wrote:
> How does Lua parse newlines? For example:
>
> print(#load('return "\\\r\n"')()) --> 1
> print(#load('return "\\\n\r"')()) --> 1
> print(#load('return "\\\r"')()) --> 1
> print(#load('return "\\\n"')()) --> 1
>
> print(load('return "\\z\r\n\\x"', "@[needed so results display 
> correctly]")) --> nil, error line at 2
> print(load('return "\\z\n\r\\x"', "@[needed so results display 
> correctly]")) --> nil, error line at 2
> print(load('return "\\z\n\\x"', "@[needed so results display 
> correctly]")) --> nil, error line at 2
> print(load('return "\\z\r\\x"', "@[needed so results display 
> correctly]")) --> nil, error line at 2
>
> So it seems that any of "\n", "\r", "\r\n" and "\n\r" are valid 
> newlines. But where in the code is it?

Quick update:

> print(load('return "\\z \n\r \n\r \r\n \n \n\\x"', "@test"))
nil    test:6: hexadecimal digit expected near '"\x"

WHY LINE 6. I NEED TO KNOW.

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