Re: Simple function (re)compilation?

[Charles Heywood <vandor2012@...>]

When f is called, a new local is set which means the function needs a new way to get that local. With g(), the local is at the same address, so it doesn't need to recompile.

On Thu, Oct 6, 2016, 8:16 AM Rodrigo Azevedo <rodrigoams@gmail.com> wrote:

Given the code:

f = function ()
        local o = 10
        return
                function(x) return x+o end
end

local o = 10
g = function ()
        return
                function(x) return x+o end
end

print(f(),f(),g(),g())

It prints:

function: 0x2196ff0    function: 0x21965f0    function: 0x2196da0    function: 0x2196da0

The problem:  Why f() returns different functions while g() does not?

--

Rodrigo Azevedo Moreira da Silva

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