Re: Rounding a number to integer

[Dirk Laurie <dirk.laurie@...>]

2016-08-03 19:30 GMT+02:00 Egor Skriptunoff <egor.skriptunoff@gmail.com>:
> On Sun, Jul 31, 2016 at 9:33 PM, Roberto Ierusalimschy
> <roberto@inf.puc-rio.br> wrote:
>>
>> What about this one?
>>
>> function round (x)
>>   return math.floor((x % 2.0 == 0.5) and x or x + 0.5)
>> end
>
>
>> (2^52+1)|0, round(2^52+1)
> 4503599627370497    4503599627370498

function round(x)
  local ans = math.floor(x)
  local err = x-ans
  if err<0.5 then return ans
  elseif err>0.5 then return ans+1
  elseif ans%2==0 then return ans
  else return ans+1
  end
end