Re: Should not integer exponentiation work when it works?

[Philipp Janda <siffiejoe@...>]

Am 09.06.2016 um 16:04 schröbte Patrick Donnelly:
> On Thu, Jun 9, 2016 at 4:45 AM, Dirk Laurie <dirk.laurie@gmail.com> wrote:
> > v=(2*n+1)^2
>
> v = (2*n+1)<<1

That would be equivalent to `(2*n+1)*2`.


Philipp