Re: Syntax error with lunitx and luajit

[Alexey Melnichuk <alexeymelnichuck@...>]

Hello.

> I'm running into an odd syntax error when running lunitx under luajit 2.0.

> $ luajit test_libcrypt.lua --help
> luajit: /usr/local/share/lua/5.1/lunit.lua:737: attempt to call global
> 'print' (a nil value)
> stack traceback:
>         /usr/local/share/lua/5.1/lunit.lua:737: in function 'main'
>         test_libcrypt.lua:44: in main chunk

To solve this one you can do `local print = print`

> #!/usr/bin/env luajit
> require('lunit')
> if _VERSION >= 'Lua 5.2' then
>     _ENV = lunit.module('test_libcrypt','seeall')
> else
>     module("test_libcrypt", lunit.testcase, package.seeall) -- mark this as a test case
> end

lunitx  has  `TEST_CASE` function to so you do not need use this `if`.
Just use this one

> local lunit = require('lunit')
> local _ENV = lunit.TEST_CASE'test_libcrypt'


> if arg[0]:match("[._%w]*$") == 'test_libcrypt.lua' then
>    lunit.main(arg)
> end

I  prefer  check  global  `lunit`  variable before `require` to detect
ether this script was run as standalone or from `lunitx.sh` or as part
of other module. I use this function

> local lunit = lunit
> local RUN = lunit and function()end or function ()
>   local res = lunit.run()
>   if res.errors + res.failed > 0 then os.exit(-1) end
>   return os.exit(0)
> end
> lunit = require "lunit"
> ...
> RUN()


PS. You can checkout my tests e.g. https://github.com/moteus/lua-gntp/blob/master/test/test.lua





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